0=(3x^2+7)-10x

Solution for 0=(3x^2+7)-10x equation:

0=(3x^2+7)-10x

We move all terms to the left:

0-((3x^2+7)-10x)=0

We add all the numbers together, and all the variables

-((3x^2+7)-10x)=0


We calculate terms in parentheses: -((3x^2+7)-10x), so:

(3x^2+7)-10x

We add all the numbers together, and all the variables

-10x+(3x^2+7)

We get rid of parentheses

3x^2-10x+7

Back to the equation:

-(3x^2-10x+7)


We get rid of parentheses

-3x^2+10x-7=0

a = -3; b = 10; c = -7;
Δ = b2-4ac
Δ = 102-4·(-3)·(-7)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-4}{2*-3}=\frac{-14}{-6}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+4}{2*-3}=\frac{-6}{-6}
=1
$